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Thought this was cool: python判断unicode是否是汉字,数字,英文,或者其他字符

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ps:中文处理经验不足,学习了。
下面这个小工具包含了 判断unicode是否是汉字,数字,英文,或者其他字符。 全角符号转半角符号。 unicode字符串归一化等工作。 还有一个能处理多音字的汉字转拼音的程序,还在整理中。
转自:
http://hi.baidu.com/fenghua1893/item/d1a71d5ac47ffdcfd3e10cd1

#!/usr/bin/env python
#
 -*- coding:GBK -*- 
 
“””汉字处理的工具:
判断unicode是否是汉字,数字,英文,或者其他字符。
全角符号转半角符号。
“””
 
def is_chinese(uchar):
        “””判断一个unicode是否是汉字“””
        if uchar >= u\u4e00 and uchar<=u\u9fa5:
                return True
        else:
                return False
 
def is_number(uchar):
        “””判断一个unicode是否是数字“””
        if uchar >= u\u0030 and uchar<=u\u0039:
                return True
        else:
                return False
 
def is_alphabet(uchar):
        “””判断一个unicode是否是英文字母“””
        if (uchar >= u\u0041 and uchar<=u\u005aor (uchar >= u\u0061 and uchar<=u\u007a):
                return True
        else:
                return False
 
def is_other(uchar):
        “””判断是否非汉字,数字和英文字符“””
        if not (is_chinese(uchar) or is_number(uchar) or is_alphabet(uchar)):
                return True
        else:
                return False
 
def B2Q(uchar):
        “””半角转全角“””
        inside_code=ord(uchar)
        if inside_code<0x0020 or inside_code>0x7e:      #不是半角字符就返回原来的字符
                return uchar
        if inside_code==0x0020: #除了空格其他的全角半角的公式为:半角=全角-0xfee0
                inside_code=0x3000
        else:
                inside_code+=0xfee0
        return unichr(inside_code)
 
def Q2B(uchar):
        “””全角转半角“””
        inside_code=ord(uchar)
        if inside_code==0x3000:
                inside_code=0x0020
        else:
                inside_code-=0xfee0
        if inside_code<0x0020 or inside_code>0x7e:      #转完之后不是半角字符返回原来的字符
                return uchar
        return unichr(inside_code)

 
def stringQ2B(ustring):
        “””把字符串全角转半角“””
        return “”.join([Q2B(uchar) for uchar in ustring])
 
def uniform(ustring):
        “””格式化字符串,完成全角转半角,大写转小写的工作“””
        return stringQ2B(ustring).lower()
 
def string2List(ustring):
        “””将ustring按照中文,字母,数字分开“””
        retList=[]
        utmp=[]
        for uchar in ustring:
                if is_other(uchar):
                        if len(utmp)==0:
                                continue
                        else:
                                retList.append(“”.join(utmp))
                                utmp=[]
                else:
                        utmp.append(uchar)
        if len(utmp)!=0:
                retList.append(“”.join(utmp))
        return retList
 
if __name__==__main__:
        #test Q2B and B2Q
        for i in range(0x0020,0x007F):
                print Q2B(B2Q(unichr(i))),B2Q(unichr(i))
 
        #test uniform
        ustring=u中国 人名a高频A
        ustring=uniform(ustring)
        ret=string2List(ustring)

        print ret

SunRise_at 2012-08-29 17:47 发表评论


from C++博客-首页原创精华区: http://www.cppblog.com/sunrise/archive/2012/08/29/188654.html

Written by cwyalpha

八月 29, 2012 在 1:07 下午

发表在 Uncategorized

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